Base | Representation |
---|---|
bin | 11000001000000011… |
… | …10101010111001111 |
3 | 1020102200101202000100 |
4 | 30010001311113033 |
5 | 203011314211341 |
6 | 5541132502143 |
7 | 635655234543 |
oct | 140401652717 |
9 | 36380352010 |
10 | 12952491471 |
11 | 5547386607 |
12 | 261591a953 |
13 | 12b55a964a |
14 | 8ac31da23 |
15 | 50c1ba3b6 |
hex | 3040755cf |
12952491471 has 24 divisors (see below), whose sum is σ = 19885076640. Its totient is φ = 8096126976.
The previous prime is 12952491457. The next prime is 12952491479. The reversal of 12952491471 is 17419425921.
12952491471 is a `hidden beast` number, since 1 + 2 + 95 + 2 + 4 + 91 + 471 = 666.
It is not a de Polignac number, because 12952491471 - 26 = 12952491407 is a prime.
It is a super-3 number, since 3×129524914713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12952491479) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 120706 + ... + 201183.
It is an arithmetic number, because the mean of its divisors is an integer number (828544860).
Almost surely, 212952491471 is an apocalyptic number.
12952491471 is a deficient number, since it is larger than the sum of its proper divisors (6932585169).
12952491471 is a wasteful number, since it uses less digits than its factorization.
12952491471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322175 (or 322172 counting only the distinct ones).
The product of its digits is 181440, while the sum is 45.
The spelling of 12952491471 in words is "twelve billion, nine hundred fifty-two million, four hundred ninety-one thousand, four hundred seventy-one".
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