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12956850013 is a prime number
BaseRepresentation
bin11000001000100100…
…11101011101011101
31020102222121011210211
430010102131131131
5203013423200023
65541410132421
7636040256632
oct140422353535
936388534724
1012956850013
115549893208
122617281111
1312b6474473
148acb36189
1550c77ba0d
hex30449d75d

12956850013 has 2 divisors, whose sum is σ = 12956850014. Its totient is φ = 12956850012.

The previous prime is 12956849929. The next prime is 12956850019. The reversal of 12956850013 is 31005865921.

12956850013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12858879609 + 97970404 = 113397^2 + 9898^2 .

It is a cyclic number.

It is not a de Polignac number, because 12956850013 - 221 = 12954752861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12956850019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6478425006 + 6478425007.

It is an arithmetic number, because the mean of its divisors is an integer number (6478425007).

Almost surely, 212956850013 is an apocalyptic number.

It is an amenable number.

12956850013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12956850013 is an equidigital number, since it uses as much as digits as its factorization.

12956850013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 40.

The spelling of 12956850013 in words is "twelve billion, nine hundred fifty-six million, eight hundred fifty thousand, thirteen".