Base | Representation |
---|---|
bin | 10010111000011011010… |
… | …111101101101011100111 |
3 | 11121001011202011012012222 |
4 | 102320123113231223213 |
5 | 132224330031342042 |
6 | 2432025322502555 |
7 | 162513143165636 |
oct | 22703327555347 |
9 | 4531152135188 |
10 | 1297539324647 |
11 | 4603131383a5 |
12 | 18b57b364a5b |
13 | 95485386317 |
14 | 46b3085351d |
15 | 23b42db62d2 |
hex | 12e1b5edae7 |
1297539324647 has 2 divisors, whose sum is σ = 1297539324648. Its totient is φ = 1297539324646.
The previous prime is 1297539324643. The next prime is 1297539324649. The reversal of 1297539324647 is 7464239357921.
It is a strong prime.
It is an emirp because it is prime and its reverse (7464239357921) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1297539324647 - 22 = 1297539324643 is a prime.
Together with 1297539324649, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1297539324647.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1297539324643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 648769662323 + 648769662324.
It is an arithmetic number, because the mean of its divisors is an integer number (648769662324).
Almost surely, 21297539324647 is an apocalyptic number.
1297539324647 is a deficient number, since it is larger than the sum of its proper divisors (1).
1297539324647 is an equidigital number, since it uses as much as digits as its factorization.
1297539324647 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 68584320, while the sum is 62.
The spelling of 1297539324647 in words is "one trillion, two hundred ninety-seven billion, five hundred thirty-nine million, three hundred twenty-four thousand, six hundred forty-seven".
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