Base | Representation |
---|---|
bin | 11000001101101010… |
… | …10110000000110101 |
3 | 1020112221221111210002 |
4 | 30012311112000311 |
5 | 203110341031411 |
6 | 5545533241045 |
7 | 640066225466 |
oct | 140665260065 |
9 | 36487844702 |
10 | 12999548981 |
11 | 55709a7611 |
12 | 2629633185 |
13 | 12c2274623 |
14 | 8b468cd6d |
15 | 5113b333b |
hex | 306d56035 |
12999548981 has 2 divisors, whose sum is σ = 12999548982. Its totient is φ = 12999548980.
The previous prime is 12999548971. The next prime is 12999548983. The reversal of 12999548981 is 18984599921.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8066734225 + 4932814756 = 89815^2 + 70234^2 .
It is a cyclic number.
It is not a de Polignac number, because 12999548981 - 222 = 12995354677 is a prime.
It is a super-2 number, since 2×129995489812 (a number of 21 digits) contains 22 as substring.
Together with 12999548983, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12999548983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6499774490 + 6499774491.
It is an arithmetic number, because the mean of its divisors is an integer number (6499774491).
Almost surely, 212999548981 is an apocalyptic number.
It is an amenable number.
12999548981 is a deficient number, since it is larger than the sum of its proper divisors (1).
12999548981 is an equidigital number, since it uses as much as digits as its factorization.
12999548981 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16796160, while the sum is 65.
The spelling of 12999548981 in words is "twelve billion, nine hundred ninety-nine million, five hundred forty-eight thousand, nine hundred eighty-one".
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