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13000011000031 = 111181819181821
BaseRepresentation
bin1011110100101100110100…
…0010011010100011011111
31201000210022010012101111001
42331023031002122203133
53200443010304000111
643352042252211131
72511135251164426
oct275131502324337
951023263171431
1013000011000031
114162301333230
12155b5a5469aa7
13733b8503a203
1432d2bd68a2bd
1517826060b1c1
hexbd2cd09a8df

13000011000031 has 4 divisors (see below), whose sum is σ = 14181830181864. Its totient is φ = 11818191818200.

The previous prime is 13000011000001. The next prime is 13000011000061.

13000011000031 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (13000011000001) and next prime (13000011000061).

It is a cyclic number.

It is not a de Polignac number, because 13000011000031 - 29 = 13000010999519 is a prime.

It is a super-2 number, since 2×130000110000312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000010999981 and 13000011000017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000011000001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590909590900 + ... + 590909590921.

It is an arithmetic number, because the mean of its divisors is an integer number (3545457545466).

Almost surely, 213000011000031 is an apocalyptic number.

13000011000031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13000011000031 is a deficient number, since it is larger than the sum of its proper divisors (1181819181833).

13000011000031 is a wasteful number, since it uses less digits than its factorization.

13000011000031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1181819181832.

The product of its (nonzero) digits is 9, while the sum is 10.

It can be divided in two parts, 1300001 and 1000031, that added together give a palindrome (2300032).

The spelling of 13000011000031 in words is "thirteen trillion, eleven million, thirty-one", and thus it is an aban number and an uban number.

Divisors: 1 11 1181819181821 13000011000031