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13000012003 = 111181819273
BaseRepresentation
bin11000001101101110…
…00111000011100011
31020112222211000221001
430012313013003203
5203111000341003
65545551212431
7640103164426
oct140667070343
936488730831
1013000012003
115571193480
122629817117
1312c23a72c4
148b476d9bd
1551145561d
hex306dc70e3

13000012003 has 4 divisors (see below), whose sum is σ = 14181831288. Its totient is φ = 11818192720.

The previous prime is 13000012001. The next prime is 13000012007. The reversal of 13000012003 is 30021000031.

13000012003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000012003 - 21 = 13000012001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13000012001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590909626 + ... + 590909647.

It is an arithmetic number, because the mean of its divisors is an integer number (3545457822).

Almost surely, 213000012003 is an apocalyptic number.

13000012003 is a deficient number, since it is larger than the sum of its proper divisors (1181819285).

13000012003 is a wasteful number, since it uses less digits than its factorization.

13000012003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1181819284.

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 13000012003 its reverse (30021000031), we get a palindrome (43021012034).

The spelling of 13000012003 in words is "thirteen billion, twelve thousand, three".

Divisors: 1 11 1181819273 13000012003