1300002000113 has 6 divisors (see below), whose sum is σ = 1380970983126. Its totient is φ = 1223531293952.

The previous prime is 1300002000103. The next prime is 1300002000239. The reversal of 1300002000113 is 3110002000031.

It can be written as a sum of positive squares in 3 ways, for example, as 795123539809 + 504878460304 = 891697^2 + 710548^2 .

It is not a de Polignac number, because 1300002000113 - 2²⁰ = 1300000951537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1300002000094 and 1300002000103.

It is not an unprimeable number, because it can be changed into a prime (1300002000103) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2249138120 + ... + 2249138697.

It is an arithmetic number, because the mean of its divisors is an integer number (230161830521).

Almost surely, 2^{1300002000113} is an apocalyptic number.

It is an amenable number.

1300002000113 is a deficient number, since it is larger than the sum of its proper divisors (80968983013).

1300002000113 is an equidigital number, since it uses as much as digits as its factorization.

1300002000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4498276851 (or 4498276834 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1300002000113 its reverse (3110002000031), we get a palindrome (4410004000144).

The spelling of 1300002000113 in words is "one trillion, three hundred billion, two million, one hundred thirteen", and thus it is an aban number.