Base | Representation |
---|---|
bin | 111100100010010011… |
… | …1011101100110110101 |
3 | 110102112221100010210112 |
4 | 1321010213131212311 |
5 | 4112220023330303 |
6 | 135415443432405 |
7 | 12251345406404 |
oct | 1710447354665 |
9 | 412487303715 |
10 | 130000214453 |
11 | 5015080626a |
12 | 21240985705 |
13 | c349c4b325 |
14 | 641352363b |
15 | 35acda70d8 |
hex | 1e449dd9b5 |
130000214453 has 2 divisors, whose sum is σ = 130000214454. Its totient is φ = 130000214452.
The previous prime is 130000214401. The next prime is 130000214459. The reversal of 130000214453 is 354412000031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66073160209 + 63927054244 = 257047^2 + 252838^2 .
It is a cyclic number.
It is not a de Polignac number, because 130000214453 - 218 = 129999952309 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130000214459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000107226 + 65000107227.
It is an arithmetic number, because the mean of its divisors is an integer number (65000107227).
Almost surely, 2130000214453 is an apocalyptic number.
It is an amenable number.
130000214453 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000214453 is an equidigital number, since it uses as much as digits as its factorization.
130000214453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 130000214453 its reverse (354412000031), we get a palindrome (484412214484).
The spelling of 130000214453 in words is "one hundred thirty billion, two hundred fourteen thousand, four hundred fifty-three".
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