Base | Representation |
---|---|
bin | 111100100010010011… |
… | …1110010100001101101 |
3 | 110102112221111111100011 |
4 | 1321010213302201231 |
5 | 4112220034101031 |
6 | 135415445333221 |
7 | 12251346214255 |
oct | 1710447624155 |
9 | 412487444304 |
10 | 130000300141 |
11 | 50150864688 |
12 | 21240a07211 |
13 | c349c7b32a |
14 | 6413546965 |
15 | 35acdc26b1 |
hex | 1e449f286d |
130000300141 has 2 divisors, whose sum is σ = 130000300142. Its totient is φ = 130000300140.
The previous prime is 130000300127. The next prime is 130000300147. The reversal of 130000300141 is 141003000031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 126330484900 + 3669815241 = 355430^2 + 60579^2 .
It is an emirp because it is prime and its reverse (141003000031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130000300141 - 217 = 130000169069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130000300147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000150070 + 65000150071.
It is an arithmetic number, because the mean of its divisors is an integer number (65000150071).
Almost surely, 2130000300141 is an apocalyptic number.
It is an amenable number.
130000300141 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000300141 is an equidigital number, since it uses as much as digits as its factorization.
130000300141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 130000300141 its reverse (141003000031), we get a palindrome (271003300172).
The spelling of 130000300141 in words is "one hundred thirty billion, three hundred thousand, one hundred forty-one".
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