Base | Representation |
---|---|
bin | 111100100010010100… |
… | …0001110000101010110 |
3 | 110102112221201020011122 |
4 | 1321010220032011112 |
5 | 4112220101204024 |
6 | 135415452003542 |
7 | 12251350164323 |
oct | 1710450160526 |
9 | 412487636148 |
10 | 130000413014 |
11 | 5015093146a |
12 | 21240a605b2 |
13 | c349cba814 |
14 | 6413575b4a |
15 | 35acde5d5e |
hex | 1e44a0e156 |
130000413014 has 4 divisors (see below), whose sum is σ = 195000619524. Its totient is φ = 65000206506.
The previous prime is 130000413007. The next prime is 130000413047. The reversal of 130000413014 is 410314000031.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 130000412983 and 130000413001.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32500103252 + ... + 32500103255.
It is an arithmetic number, because the mean of its divisors is an integer number (48750154881).
Almost surely, 2130000413014 is an apocalyptic number.
130000413014 is a deficient number, since it is larger than the sum of its proper divisors (65000206510).
130000413014 is an equidigital number, since it uses as much as digits as its factorization.
130000413014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65000206509.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130000413014 its reverse (410314000031), we get a palindrome (540314413045).
The spelling of 130000413014 in words is "one hundred thirty billion, four hundred thirteen thousand, fourteen".
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