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130000465207 is a prime number
BaseRepresentation
bin111100100010010100…
…0011010110100110111
3110102112221210212202201
41321010220122310313
54112220104341312
6135415453045331
712251350502434
oct1710450326467
9412487725681
10130000465207
11501509676a8
1221240a86847
13c34a0084c2
14641358ab8b
1535ace06557
hex1e44a1ad37

130000465207 has 2 divisors, whose sum is σ = 130000465208. Its totient is φ = 130000465206.

The previous prime is 130000465159. The next prime is 130000465249. The reversal of 130000465207 is 702564000031.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130000465207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130000465277) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000232603 + 65000232604.

It is an arithmetic number, because the mean of its divisors is an integer number (65000232604).

Almost surely, 2130000465207 is an apocalyptic number.

130000465207 is a deficient number, since it is larger than the sum of its proper divisors (1).

130000465207 is an equidigital number, since it uses as much as digits as its factorization.

130000465207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 28.

Adding to 130000465207 its reverse (702564000031), we get a palindrome (832564465238).

The spelling of 130000465207 in words is "one hundred thirty billion, four hundred sixty-five thousand, two hundred seven".