Base | Representation |
---|---|
bin | 111100100010010100… |
… | …0011010110101100001 |
3 | 110102112221210212211021 |
4 | 1321010220122311201 |
5 | 4112220104341444 |
6 | 135415453045441 |
7 | 12251350502524 |
oct | 1710450326541 |
9 | 412487725737 |
10 | 130000465249 |
11 | 50150967736 |
12 | 21240a86881 |
13 | c34a008525 |
14 | 641358abbb |
15 | 35ace06584 |
hex | 1e44a1ad61 |
130000465249 has 2 divisors, whose sum is σ = 130000465250. Its totient is φ = 130000465248.
The previous prime is 130000465207. The next prime is 130000465277. The reversal of 130000465249 is 942564000031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129729632400 + 270832849 = 360180^2 + 16457^2 .
It is a cyclic number.
It is not a de Polignac number, because 130000465249 - 213 = 130000457057 is a prime.
It is not a weakly prime, because it can be changed into another prime (130000465279) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000232624 + 65000232625.
It is an arithmetic number, because the mean of its divisors is an integer number (65000232625).
Almost surely, 2130000465249 is an apocalyptic number.
It is an amenable number.
130000465249 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000465249 is an equidigital number, since it uses as much as digits as its factorization.
130000465249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 34.
The spelling of 130000465249 in words is "one hundred thirty billion, four hundred sixty-five thousand, two hundred forty-nine".
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