Base | Representation |
---|---|
bin | 111100100010010101… |
… | …0001000101110010111 |
3 | 110102112222122202020201 |
4 | 1321010222020232113 |
5 | 4112220213242401 |
6 | 135415510441331 |
7 | 12251354356006 |
oct | 1710452105627 |
9 | 412488582221 |
10 | 130000915351 |
11 | 5015114491a |
12 | 21241063247 |
13 | c34a135368 |
14 | 6413666c3d |
15 | 35ace94b01 |
hex | 1e44a88b97 |
130000915351 has 2 divisors, whose sum is σ = 130000915352. Its totient is φ = 130000915350.
The previous prime is 130000915349. The next prime is 130000915391. The reversal of 130000915351 is 153519000031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130000915351 - 21 = 130000915349 is a prime.
Together with 130000915349, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130000915321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000457675 + 65000457676.
It is an arithmetic number, because the mean of its divisors is an integer number (65000457676).
Almost surely, 2130000915351 is an apocalyptic number.
130000915351 is a deficient number, since it is larger than the sum of its proper divisors (1).
130000915351 is an equidigital number, since it uses as much as digits as its factorization.
130000915351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 28.
Adding to 130000915351 its reverse (153519000031), we get a palindrome (283519915382).
The spelling of 130000915351 in words is "one hundred thirty billion, nine hundred fifteen thousand, three hundred fifty-one".
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