Base | Representation |
---|---|
bin | 111100100010010101… |
… | …0100010100110011101 |
3 | 110102112222212010122021 |
4 | 1321010222202212131 |
5 | 4112220230140331 |
6 | 135415513020141 |
7 | 12251355310012 |
oct | 1710452424635 |
9 | 412488763567 |
10 | 130001021341 |
11 | 50151207514 |
12 | 212410b4651 |
13 | c34a171689 |
14 | 6413693709 |
15 | 35aceb6211 |
hex | 1e44aa299d |
130001021341 has 2 divisors, whose sum is σ = 130001021342. Its totient is φ = 130001021340.
The previous prime is 130001021321. The next prime is 130001021369. The reversal of 130001021341 is 143120100031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82812148441 + 47188872900 = 287771^2 + 217230^2 .
It is a cyclic number.
It is not a de Polignac number, because 130001021341 - 25 = 130001021309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130001021321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65000510670 + 65000510671.
It is an arithmetic number, because the mean of its divisors is an integer number (65000510671).
Almost surely, 2130001021341 is an apocalyptic number.
It is an amenable number.
130001021341 is a deficient number, since it is larger than the sum of its proper divisors (1).
130001021341 is an equidigital number, since it uses as much as digits as its factorization.
130001021341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 130001021341 its reverse (143120100031), we get a palindrome (273121121372).
The spelling of 130001021341 in words is "one hundred thirty billion, one million, twenty-one thousand, three hundred forty-one".
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