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13000103113 = 31760076827
BaseRepresentation
bin11000001101101110…
…11101010011001001
31020112222222122220111
430012313131103021
5203111011244423
65545553154321
7640104024154
oct140667352311
936488878814
1013000103113
115571245978
12262985b9a1
1312c240990a
148b4794c9b
1551147260d
hex306ddd4c9

13000103113 has 8 divisors (see below), whose sum is σ = 13045194432. Its totient is φ = 12955038096.

The previous prime is 13000103101. The next prime is 13000103117. The reversal of 13000103113 is 31130100031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000103113 - 29 = 13000102601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13000103093 and 13000103102.

It is not an unprimeable number, because it can be changed into a prime (13000103117) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1900806 + ... + 1907632.

It is an arithmetic number, because the mean of its divisors is an integer number (1630649304).

Almost surely, 213000103113 is an apocalyptic number.

It is an amenable number.

13000103113 is a deficient number, since it is larger than the sum of its proper divisors (45091319).

13000103113 is an equidigital number, since it uses as much as digits as its factorization.

13000103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13151.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 13000103113 its reverse (31130100031), we get a palindrome (44130203144).

The spelling of 13000103113 in words is "thirteen billion, one hundred three thousand, one hundred thirteen".

Divisors: 1 317 6007 6827 1904219 2164159 41009789 13000103113