13000103231231 has 4 divisors (see below), whose sum is σ = 13245388197912. Its totient is φ = 12754818264552.

The previous prime is 13000103231201. The next prime is 13000103231239. The reversal of 13000103231231 is 13213230100031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000103231231 - 2¹⁰ = 13000103230207 is a prime.

It is a super-2 number, since 2×13000103231231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000103231239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122642483261 + ... + 122642483366.

It is an arithmetic number, because the mean of its divisors is an integer number (3311347049478).

Almost surely, 2^{13000103231231} is an apocalyptic number.

13000103231231 is a deficient number, since it is larger than the sum of its proper divisors (245284966681).

13000103231231 is an equidigital number, since it uses as much as digits as its factorization.

13000103231231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 245284966680.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13000103231231 its reverse (13213230100031), we get a palindrome (26213333331262).

The spelling of 13000103231231 in words is "thirteen trillion, one hundred three million, two hundred thirty-one thousand, two hundred thirty-one".