Search a number
-
+
13000113 = 327206351
BaseRepresentation
bin110001100101…
…110110110001
3220110110210200
4301211312301
511312000423
61142345413
7215333130
oct61456661
926413720
1013000113
11737a1a5
12442b269
132902299
141a25917
15121bd43
hexc65db1

13000113 has 12 divisors (see below), whose sum is σ = 21460608. Its totient is φ = 7428600.

The previous prime is 13000081. The next prime is 13000133. The reversal of 13000113 is 31100031.

It is not a de Polignac number, because 13000113 - 25 = 13000081 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is a junction number, because it is equal to n+sod(n) for n = 13000095 and 13000104.

It is not an unprimeable number, because it can be changed into a prime (13000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 103113 + ... + 103238.

It is an arithmetic number, because the mean of its divisors is an integer number (1788384).

Almost surely, 213000113 is an apocalyptic number.

It is an amenable number.

13000113 is a deficient number, since it is larger than the sum of its proper divisors (8460495).

13000113 is a wasteful number, since it uses less digits than its factorization.

13000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 206364 (or 206361 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

The square root of 13000113 is about 3605.5669457105. The cubic root of 13000113 is about 235.1341500543.

Adding to 13000113 its reverse (31100031), we get a palindrome (44100144).

The spelling of 13000113 in words is "thirteen million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 3 7 9 21 63 206351 619053 1444457 1857159 4333371 13000113