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13000114321 is a prime number
BaseRepresentation
bin11000001101101111…
…00000000010010001
31020120000000020021121
430012313200002101
5203111012124241
65545553322241
7640104101635
oct140667400221
936500006247
1013000114321
115571253337
122629866381
1312c2411a4c
148b4798dc5
15511475ad1
hex306de0091

13000114321 has 2 divisors, whose sum is σ = 13000114322. Its totient is φ = 13000114320.

The previous prime is 13000114301. The next prime is 13000114333. The reversal of 13000114321 is 12341100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10289870721 + 2710243600 = 101439^2 + 52060^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13000114321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13000114295 and 13000114304.

It is not a weakly prime, because it can be changed into another prime (13000114301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500057160 + 6500057161.

It is an arithmetic number, because the mean of its divisors is an integer number (6500057161).

Almost surely, 213000114321 is an apocalyptic number.

It is an amenable number.

13000114321 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000114321 is an equidigital number, since it uses as much as digits as its factorization.

13000114321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13000114321 its reverse (12341100031), we get a palindrome (25341214352).

The spelling of 13000114321 in words is "thirteen billion, one hundred fourteen thousand, three hundred twenty-one".