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130001203301 = 130799465343
BaseRepresentation
bin111100100010010101…
…1001111000001100101
3110102120000012101020112
41321010223033001211
54112220302001201
6135415520542405
712251356665344
oct1710453170145
9412500171215
10130001203301
11501513211a2
1221241181a05
13c34a206448
1464136ddb5b
1535ad0000bb
hex1e44acf065

130001203301 has 4 divisors (see below), whose sum is σ = 130100669952. Its totient is φ = 129901736652.

The previous prime is 130001203249. The next prime is 130001203349. The reversal of 130001203301 is 103302100031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130001203301 - 26 = 130001203237 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130001203391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49731365 + ... + 49733978.

It is an arithmetic number, because the mean of its divisors is an integer number (32525167488).

Almost surely, 2130001203301 is an apocalyptic number.

It is an amenable number.

130001203301 is a deficient number, since it is larger than the sum of its proper divisors (99466651).

130001203301 is an equidigital number, since it uses as much as digits as its factorization.

130001203301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99466650.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 130001203301 its reverse (103302100031), we get a palindrome (233303303332).

The spelling of 130001203301 in words is "one hundred thirty billion, one million, two hundred three thousand, three hundred one".

Divisors: 1 1307 99465343 130001203301