1300012114073 has 2 divisors, whose sum is σ = 1300012114074. Its totient is φ = 1300012114072.

The previous prime is 1300012114069. The next prime is 1300012114081. The reversal of 1300012114073 is 3704112100031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 943235267209 + 356776846864 = 971203^2 + 597308^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300012114073 - 2² = 1300012114069 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300012114003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006057036 + 650006057037.

It is an arithmetic number, because the mean of its divisors is an integer number (650006057037).

Almost surely, 2^{1300012114073} is an apocalyptic number.

It is an amenable number.

1300012114073 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300012114073 is an equidigital number, since it uses as much as digits as its factorization.

1300012114073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The spelling of 1300012114073 in words is "one trillion, three hundred billion, twelve million, one hundred fourteen thousand, seventy-three".