1300012114217 has 2 divisors, whose sum is σ = 1300012114218. Its totient is φ = 1300012114216.

The previous prime is 1300012114201. The next prime is 1300012114223. The reversal of 1300012114217 is 7124112100031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1288397525776 + 11614588441 = 1135076^2 + 107771^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300012114217 - 2⁴ = 1300012114201 is a prime.

It is a super-2 number, since 2×1300012114217² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300012114192 and 1300012114201.

It is not a weakly prime, because it can be changed into another prime (1300012114267) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006057108 + 650006057109.

It is an arithmetic number, because the mean of its divisors is an integer number (650006057109).

Almost surely, 2^{1300012114217} is an apocalyptic number.

It is an amenable number.

1300012114217 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300012114217 is an equidigital number, since it uses as much as digits as its factorization.

1300012114217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 1300012114217 its reverse (7124112100031), we get a palindrome (8424124214248).

The spelling of 1300012114217 in words is "one trillion, three hundred billion, twelve million, one hundred fourteen thousand, two hundred seventeen".