Base | Representation |
---|---|
bin | 10010111010101110110… |
… | …100110101111001011011 |
3 | 11121021120011012122121212 |
4 | 102322232310311321123 |
5 | 132244411340224402 |
6 | 2433115014453335 |
7 | 162631352654153 |
oct | 22725664657133 |
9 | 4537504178555 |
10 | 1300013211227 |
11 | 461372625a65 |
12 | 18bb4b96424b |
13 | 9578aa71833 |
14 | 46cc7227763 |
15 | 23c3a184952 |
hex | 12eaed35e5b |
1300013211227 has 2 divisors, whose sum is σ = 1300013211228. Its totient is φ = 1300013211226.
The previous prime is 1300013211197. The next prime is 1300013211229. The reversal of 1300013211227 is 7221123100031.
It is a strong prime.
It is an emirp because it is prime and its reverse (7221123100031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1300013211227 - 230 = 1298939469403 is a prime.
Together with 1300013211229, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1300013211229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650006605613 + 650006605614.
It is an arithmetic number, because the mean of its divisors is an integer number (650006605614).
Almost surely, 21300013211227 is an apocalyptic number.
1300013211227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300013211227 is an equidigital number, since it uses as much as digits as its factorization.
1300013211227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 1300013211227 its reverse (7221123100031), we get a palindrome (8521136311258).
The spelling of 1300013211227 in words is "one trillion, three hundred billion, thirteen million, two hundred eleven thousand, two hundred twenty-seven".
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