Base | Representation |
---|---|
bin | 10010111010101110110… |
… | …100110110101001101001 |
3 | 11121021120011012210212011 |
4 | 102322232310312221221 |
5 | 132244411340324223 |
6 | 2433115014515521 |
7 | 162631352666152 |
oct | 22725664665151 |
9 | 4537504183764 |
10 | 1300013214313 |
11 | 461372628310 |
12 | 18bb4b965ba1 |
13 | 9578aa73068 |
14 | 46cc7228929 |
15 | 23c3a18580d |
hex | 12eaed36a69 |
1300013214313 has 8 divisors (see below), whose sum is σ = 1435282936416. Its totient is φ = 1167591276000.
The previous prime is 1300013214287. The next prime is 1300013214319. The reversal of 1300013214313 is 3134123100031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1300013214313 - 221 = 1300011117161 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1300013214319) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 711944988 + ... + 711946813.
It is an arithmetic number, because the mean of its divisors is an integer number (179410367052).
Almost surely, 21300013214313 is an apocalyptic number.
It is an amenable number.
1300013214313 is a deficient number, since it is larger than the sum of its proper divisors (135269722103).
1300013214313 is a wasteful number, since it uses less digits than its factorization.
1300013214313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1423891895.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1300013214313 its reverse (3134123100031), we get a palindrome (4434136314344).
The spelling of 1300013214313 in words is "one trillion, three hundred billion, thirteen million, two hundred fourteen thousand, three hundred thirteen".
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