1300013900 has 18 divisors (see below), whose sum is σ = 2821030380. Its totient is φ = 520005520.

The previous prime is 1300013879. The next prime is 1300013903. The reversal of 1300013900 is 93100031.

It is a super-2 number, since 2×1300013900² = 3380072280386420000, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1300013903) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6499970 + ... + 6500169.

It is an arithmetic number, because the mean of its divisors is an integer number (156723910).

Almost surely, 2^1300013900 is an apocalyptic number.

1300013900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1300013900 is an abundant number, since it is smaller than the sum of its proper divisors (1521016480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300013900 is a wasteful number, since it uses less digits than its factorization.

1300013900 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13000153 (or 13000146 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

The square root of 1300013900 is about 36055.7055124428. The cubic root of 1300013900 is about 1091.3967728834.

Adding to 1300013900 its reverse (93100031), we get a palindrome (1393113931).

The spelling of 1300013900 in words is "one billion, three hundred million, thirteen thousand, nine hundred".