13000200413 has 2 divisors, whose sum is σ = 13000200414. Its totient is φ = 13000200412.

The previous prime is 13000200403. The next prime is 13000200431. The reversal of 13000200413 is 31400200031.

Together with next prime (13000200431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12986197849 + 14002564 = 113957^2 + 3742^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000200413 - 2²² = 12996006109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000200403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500100206 + 6500100207.

It is an arithmetic number, because the mean of its divisors is an integer number (6500100207).

Almost surely, 2^13000200413 is an apocalyptic number.

It is an amenable number.

13000200413 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000200413 is an equidigital number, since it uses as much as digits as its factorization.

13000200413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 13000200413 its reverse (31400200031), we get a palindrome (44400400444).

The spelling of 13000200413 in words is "thirteen billion, two hundred thousand, four hundred thirteen".