Base | Representation |
---|---|
bin | 11101100011110001110100… |
… | …111001010111010101111011 |
3 | 122001022001222002021112112001 |
4 | 131203301310321113111323 |
5 | 114014423130003411303 |
6 | 1140254035252001431 |
7 | 36245223345436603 |
oct | 3543616471272573 |
9 | 561261862245461 |
10 | 130002031310203 |
11 | 3847160858a698 |
12 | 126b7321300277 |
13 | 57701a63729a0 |
14 | 24161bbc87c03 |
15 | 10069b7a9331d |
hex | 763c74e5757b |
130002031310203 has 4 divisors (see below), whose sum is σ = 140002187564848. Its totient is φ = 120001875055560.
The previous prime is 130002031310191. The next prime is 130002031310231. The reversal of 130002031310203 is 302013130200031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130002031310203 - 217 = 130002031179131 is a prime.
It is a super-2 number, since 2×1300020313102032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130002032310203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000078127303 + ... + 5000078127328.
It is an arithmetic number, because the mean of its divisors is an integer number (35000546891212).
Almost surely, 2130002031310203 is an apocalyptic number.
130002031310203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130002031310203 is a deficient number, since it is larger than the sum of its proper divisors (10000156254645).
130002031310203 is a wasteful number, since it uses less digits than its factorization.
130002031310203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10000156254644.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 130002031310203 its reverse (302013130200031), we get a palindrome (432015161510234).
The spelling of 130002031310203 in words is "one hundred thirty trillion, two billion, thirty-one million, three hundred ten thousand, two hundred three".
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