1300020332413 has 4 divisors (see below), whose sum is σ = 1418203999008. Its totient is φ = 1181836665820.

The previous prime is 1300020332399. The next prime is 1300020332423. The reversal of 1300020332413 is 3142330200031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300020332413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300020332423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59091833281 + ... + 59091833302.

It is an arithmetic number, because the mean of its divisors is an integer number (354550999752).

Almost surely, 2^{1300020332413} is an apocalyptic number.

It is an amenable number.

1300020332413 is a deficient number, since it is larger than the sum of its proper divisors (118183666595).

1300020332413 is a wasteful number, since it uses less digits than its factorization.

1300020332413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118183666594.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 1300020332413 its reverse (3142330200031), we get a palindrome (4442350532444).

The spelling of 1300020332413 in words is "one trillion, three hundred billion, twenty million, three hundred thirty-two thousand, four hundred thirteen".