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130002113 = 1394492083
BaseRepresentation
bin1111011111110…
…10110011000001
3100001121210101002
413233322303001
5231240031423
620522221345
73135666623
oct757726301
9301553332
10130002113
116742356a
1237654855
1320c19737
14133a0c13
15b62e228
hex7bfacc1

130002113 has 8 divisors (see below), whose sum is σ = 131292000. Its totient is φ = 128717568.

The previous prime is 130002109. The next prime is 130002133. The reversal of 130002113 is 311200031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130002113 - 22 = 130002109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130002094 and 130002103.

It is not an unprimeable number, because it can be changed into a prime (130002133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 61370 + ... + 63452.

It is an arithmetic number, because the mean of its divisors is an integer number (16411500).

Almost surely, 2130002113 is an apocalyptic number.

It is an amenable number.

130002113 is a deficient number, since it is larger than the sum of its proper divisors (1289887).

130002113 is a wasteful number, since it uses less digits than its factorization.

130002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2671.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 130002113 is about 11401.8469117946. The cubic root of 130002113 is about 506.5824465181.

Adding to 130002113 its reverse (311200031), we get a palindrome (441202144).

The spelling of 130002113 in words is "one hundred thirty million, two thousand, one hundred thirteen".

Divisors: 1 139 449 2083 62411 289537 935267 130002113