130002313111 has 4 divisors (see below), whose sum is σ = 141820705224. Its totient is φ = 118183921000.

The previous prime is 130002313097. The next prime is 130002313151. The reversal of 130002313111 is 111313200031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111313200031 = 11 ⋅10119381821.

It is a cyclic number.

It is not a de Polignac number, because 130002313111 - 2²⁵ = 129968758679 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130002313151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5909196040 + ... + 5909196061.

It is an arithmetic number, because the mean of its divisors is an integer number (35455176306).

Almost surely, 2^130002313111 is an apocalyptic number.

130002313111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

130002313111 is a deficient number, since it is larger than the sum of its proper divisors (11818392113).

130002313111 is a wasteful number, since it uses less digits than its factorization.

130002313111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11818392112.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 130002313111 its reverse (111313200031), we get a palindrome (241315513142).

The spelling of 130002313111 in words is "one hundred thirty billion, two million, three hundred thirteen thousand, one hundred eleven".