130002743303 has 2 divisors, whose sum is σ = 130002743304. Its totient is φ = 130002743302.

The previous prime is 130002743279. The next prime is 130002743327. The reversal of 130002743303 is 303347200031.

It is a balanced prime because it is at equal distance from previous prime (130002743279) and next prime (130002743327).

It is a cyclic number.

It is not a de Polignac number, because 130002743303 - 2⁶ = 130002743239 is a prime.

It is a super-2 number, since 2×130002743303² (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130002743803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65001371651 + 65001371652.

It is an arithmetic number, because the mean of its divisors is an integer number (65001371652).

Almost surely, 2^130002743303 is an apocalyptic number.

130002743303 is a deficient number, since it is larger than the sum of its proper divisors (1).

130002743303 is an equidigital number, since it uses as much as digits as its factorization.

130002743303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536, while the sum is 26.

Adding to 130002743303 its reverse (303347200031), we get a palindrome (433349943334).

The spelling of 130002743303 in words is "one hundred thirty billion, two million, seven hundred forty-three thousand, three hundred three".