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13000299989 is a prime number
BaseRepresentation
bin11000001101110000…
…01101010111010101
31020120000100122222012
430012320031113111
5203111034044424
65550001314005
7640105504145
oct140670152725
936500318865
1013000299989
11557136a886
122629935905
1312c2478401
148b4806925
155114b0b0e
hex306e0d5d5

13000299989 has 2 divisors, whose sum is σ = 13000299990. Its totient is φ = 13000299988.

The previous prime is 13000299943. The next prime is 13000300013. The reversal of 13000299989 is 98999200031.

13000299989 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12946571089 + 53728900 = 113783^2 + 7330^2 .

It is a cyclic number.

It is not a de Polignac number, because 13000299989 - 28 = 13000299733 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13000299919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500149994 + 6500149995.

It is an arithmetic number, because the mean of its divisors is an integer number (6500149995).

Almost surely, 213000299989 is an apocalyptic number.

It is an amenable number.

13000299989 is a deficient number, since it is larger than the sum of its proper divisors (1).

13000299989 is an equidigital number, since it uses as much as digits as its factorization.

13000299989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 314928, while the sum is 50.

The spelling of 13000299989 in words is "thirteen billion, two hundred ninety-nine thousand, nine hundred eighty-nine".