Base | Representation |
---|---|
bin | 10010111010101111111… |
… | …001110110010110011111 |
3 | 11121021121102020201011022 |
4 | 102322233321312112133 |
5 | 132244431003113043 |
6 | 2433120502314355 |
7 | 162631662506120 |
oct | 22725771662637 |
9 | 4537542221138 |
10 | 1300031301023 |
11 | 461381861104 |
12 | 18bb55a289bb |
13 | 95791736660 |
14 | 46cc97b6047 |
15 | 23c3ba59868 |
hex | 12eafe7659f |
1300031301023 has 32 divisors (see below), whose sum is σ = 1610931840000. Its totient is φ = 1021603415040.
The previous prime is 1300031300957. The next prime is 1300031301067. The reversal of 1300031301023 is 3201031300031.
It is not a de Polignac number, because 1300031301023 - 234 = 1282851431839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1300031300992 and 1300031301010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300031301623) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18946808 + ... + 19015298.
It is an arithmetic number, because the mean of its divisors is an integer number (50341620000).
Almost surely, 21300031301023 is an apocalyptic number.
1300031301023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1300031301023 is a deficient number, since it is larger than the sum of its proper divisors (310900538977).
1300031301023 is a wasteful number, since it uses less digits than its factorization.
1300031301023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69927.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1300031301023 its reverse (3201031300031), we get a palindrome (4501062601054).
The spelling of 1300031301023 in words is "one trillion, three hundred billion, thirty-one million, three hundred one thousand, twenty-three".
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