13000324341 has 8 divisors (see below), whose sum is σ = 17353854720. Its totient is φ = 8656838432.

The previous prime is 13000324291. The next prime is 13000324397. The reversal of 13000324341 is 14342300031.

13000324341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13000324341 - 2¹³ = 13000316149 is a prime.

It is a super-3 number, since 3×13000324341³ (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000324741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2508096 + ... + 2513273.

It is an arithmetic number, because the mean of its divisors is an integer number (2169231840).

Almost surely, 2^13000324341 is an apocalyptic number.

It is an amenable number.

13000324341 is a deficient number, since it is larger than the sum of its proper divisors (4353530379).

13000324341 is an equidigital number, since it uses as much as digits as its factorization.

13000324341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5022235.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 13000324341 its reverse (14342300031), we get a palindrome (27342624372).

The spelling of 13000324341 in words is "thirteen billion, three hundred twenty-four thousand, three hundred forty-one".