13000330211 has 4 divisors (see below), whose sum is σ = 14182178424. Its totient is φ = 11818482000.

The previous prime is 13000330171. The next prime is 13000330247. The reversal of 13000330211 is 11203300031.

13000330211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13000330211 - 2¹⁰ = 13000329187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13000300211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590924090 + ... + 590924111.

It is an arithmetic number, because the mean of its divisors is an integer number (3545544606).

Almost surely, 2^13000330211 is an apocalyptic number.

13000330211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13000330211 is a deficient number, since it is larger than the sum of its proper divisors (1181848213).

13000330211 is a wasteful number, since it uses less digits than its factorization.

13000330211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1181848212.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 13000330211 its reverse (11203300031), we get a palindrome (24203630242).

The spelling of 13000330211 in words is "thirteen billion, three hundred thirty thousand, two hundred eleven".