Base | Representation |
---|---|
bin | 11000001101110000… |
… | …10101000000100100 |
3 | 1020120000102020220212 |
4 | 30012320111000210 |
5 | 203111041100200 |
6 | 5550002114552 |
7 | 640105664345 |
oct | 140670250044 |
9 | 36500366825 |
10 | 13000331300 |
11 | 5571391360 |
12 | 262994ba58 |
13 | 12c2489738 |
14 | 8b48140cc |
15 | 5114ba035 |
hex | 306e15024 |
13000331300 has 36 divisors (see below), whose sum is σ = 30775332336. Its totient is φ = 4727392800.
The previous prime is 13000331287. The next prime is 13000331321. The reversal of 13000331300 is 313300031.
It is a super-2 number, since 2×130003313002 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5908142 + ... + 5910341.
Almost surely, 213000331300 is an apocalyptic number.
13000331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13000331300 is an abundant number, since it is smaller than the sum of its proper divisors (17775001036).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13000331300 is a wasteful number, since it uses less digits than its factorization.
13000331300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11818508 (or 11818501 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 14.
Adding to 13000331300 its reverse (313300031), we get a palindrome (13313631331).
The spelling of 13000331300 in words is "thirteen billion, three hundred thirty-one thousand, three hundred".
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