Search a number
-
+
130003342421 = 244753127643
BaseRepresentation
bin111100100010011001…
…1011001010001010101
3110102120011020001120012
41321010303121101111
54112221323424141
6135420034450005
712251414115011
oct1710463312125
9412504201505
10130003342421
1150152552367
1221241a33905
13c34a7a4cb4
146413ad9541
1535ad2c3ceb
hex1e44cd9455

130003342421 has 4 divisors (see below), whose sum is σ = 130056472512. Its totient is φ = 129950212332.

The previous prime is 130003342397. The next prime is 130003342489. The reversal of 130003342421 is 124243300031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130003342421 - 210 = 130003341397 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130003342921) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26561375 + ... + 26566268.

It is an arithmetic number, because the mean of its divisors is an integer number (32514118128).

Almost surely, 2130003342421 is an apocalyptic number.

It is an amenable number.

130003342421 is a deficient number, since it is larger than the sum of its proper divisors (53130091).

130003342421 is an equidigital number, since it uses as much as digits as its factorization.

130003342421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53130090.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 130003342421 its reverse (124243300031), we get a palindrome (254246642452).

The spelling of 130003342421 in words is "one hundred thirty billion, three million, three hundred forty-two thousand, four hundred twenty-one".

Divisors: 1 2447 53127643 130003342421