13000340112 has 40 divisors (see below), whose sum is σ = 33685716000. Its totient is φ = 4320349440.

The previous prime is 13000340077. The next prime is 13000340137. The reversal of 13000340112 is 21104300031.

It is a junction number, because it is equal to n+sod(n) for n = 13000340091 and 13000340100.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 393237 + ... + 425012.

It is an arithmetic number, because the mean of its divisors is an integer number (842142900).

Almost surely, 2^13000340112 is an apocalyptic number.

13000340112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13000340112 is an abundant number, since it is smaller than the sum of its proper divisors (20685375888).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13000340112 is a wasteful number, since it uses less digits than its factorization.

13000340112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 818591 (or 818585 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13000340112 its reverse (21104300031), we get a palindrome (34104640143).

The spelling of 13000340112 in words is "thirteen billion, three hundred forty thousand, one hundred twelve".