1300034124341 has 4 divisors (see below), whose sum is σ = 1313436538092. Its totient is φ = 1286631710592.

The previous prime is 1300034124317. The next prime is 1300034124343. The reversal of 1300034124341 is 1434214300031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1024326168100 + 275707956241 = 1012090^2 + 525079^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300034124341 - 2²² = 1300029930037 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1300034124341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300034124343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6701206730 + ... + 6701206923.

It is an arithmetic number, because the mean of its divisors is an integer number (328359134523).

Almost surely, 2^{1300034124341} is an apocalyptic number.

It is an amenable number.

1300034124341 is a deficient number, since it is larger than the sum of its proper divisors (13402413751).

1300034124341 is an equidigital number, since it uses as much as digits as its factorization.

1300034124341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13402413750.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 1300034124341 its reverse (1434214300031), we get a palindrome (2734248424372).

The spelling of 1300034124341 in words is "one trillion, three hundred billion, thirty-four million, one hundred twenty-four thousand, three hundred forty-one".