1300034142007 has 2 divisors, whose sum is σ = 1300034142008. Its totient is φ = 1300034142006.

The previous prime is 1300034141981. The next prime is 1300034142049. The reversal of 1300034142007 is 7002414300031.

It is a weak prime.

It is an emirp because it is prime and its reverse (7002414300031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1300034142007 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300034542007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650017071003 + 650017071004.

It is an arithmetic number, because the mean of its divisors is an integer number (650017071004).

Almost surely, 2^{1300034142007} is an apocalyptic number.

1300034142007 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300034142007 is an equidigital number, since it uses as much as digits as its factorization.

1300034142007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 1300034142007 its reverse (7002414300031), we get a palindrome (8302448442038).

The spelling of 1300034142007 in words is "one trillion, three hundred billion, thirty-four million, one hundred forty-two thousand, seven".