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130004120143 is a prime number
BaseRepresentation
bin111100100010011011…
…0010111001001001111
3110102120012200120101201
41321010312113021033
54112222023321033
6135420103250331
712251423534302
oct1710466271117
9412505616351
10130004120143
1150152a33707
12212421499a7
13c34a9b7ca1
146413c5cb39
1535ad3c947d
hex1e44d9724f

130004120143 has 2 divisors, whose sum is σ = 130004120144. Its totient is φ = 130004120142.

The previous prime is 130004120089. The next prime is 130004120149. The reversal of 130004120143 is 341021400031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130004120143 - 233 = 121414185551 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130004120143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130004120149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65002060071 + 65002060072.

It is an arithmetic number, because the mean of its divisors is an integer number (65002060072).

Almost surely, 2130004120143 is an apocalyptic number.

130004120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

130004120143 is an equidigital number, since it uses as much as digits as its factorization.

130004120143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 130004120143 its reverse (341021400031), we get a palindrome (471025520174).

The spelling of 130004120143 in words is "one hundred thirty billion, four million, one hundred twenty thousand, one hundred forty-three".