Base | Representation |
---|---|
bin | 111100100010011011… |
… | …0010111001001001111 |
3 | 110102120012200120101201 |
4 | 1321010312113021033 |
5 | 4112222023321033 |
6 | 135420103250331 |
7 | 12251423534302 |
oct | 1710466271117 |
9 | 412505616351 |
10 | 130004120143 |
11 | 50152a33707 |
12 | 212421499a7 |
13 | c34a9b7ca1 |
14 | 6413c5cb39 |
15 | 35ad3c947d |
hex | 1e44d9724f |
130004120143 has 2 divisors, whose sum is σ = 130004120144. Its totient is φ = 130004120142.
The previous prime is 130004120089. The next prime is 130004120149. The reversal of 130004120143 is 341021400031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130004120143 - 233 = 121414185551 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130004120143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130004120149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65002060071 + 65002060072.
It is an arithmetic number, because the mean of its divisors is an integer number (65002060072).
Almost surely, 2130004120143 is an apocalyptic number.
130004120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
130004120143 is an equidigital number, since it uses as much as digits as its factorization.
130004120143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 130004120143 its reverse (341021400031), we get a palindrome (471025520174).
The spelling of 130004120143 in words is "one hundred thirty billion, four million, one hundred twenty thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •