13000481653 has 4 divisors (see below), whose sum is σ = 13351846060. Its totient is φ = 12649117248.

The previous prime is 13000481639. The next prime is 13000481677. The reversal of 13000481653 is 35618400031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5441570289 + 7558911364 = 73767^2 + 86942^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13000481653 is a prime.

It is a super-2 number, since 2×13000481653² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13000481623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175682148 + ... + 175682221.

It is an arithmetic number, because the mean of its divisors is an integer number (3337961515).

Almost surely, 2^13000481653 is an apocalyptic number.

It is an amenable number.

13000481653 is a deficient number, since it is larger than the sum of its proper divisors (351364407).

13000481653 is an equidigital number, since it uses as much as digits as its factorization.

13000481653 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 351364406.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13000481653 its reverse (35618400031), we get a palindrome (48618881684).

The spelling of 13000481653 in words is "thirteen billion, four hundred eighty-one thousand, six hundred fifty-three".