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130006115 = 531383071
BaseRepresentation
bin1111011111110…
…11110001100011
3100001121222212022
413233323301203
5231240143430
620522252055
73136014401
oct757736143
9301558768
10130006115
1167426578
123765702b
1320c1b4c5
14133a2471
15b6304e5
hex7bfbc63

130006115 has 8 divisors (see below), whose sum is σ = 156507648. Its totient is φ = 103671360.

The previous prime is 130006109. The next prime is 130006117. The reversal of 130006115 is 511600031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 130006115 - 222 = 125811811 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130006093 and 130006102.

It is not an unprimeable number, because it can be changed into a prime (130006117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39971 + ... + 43100.

It is an arithmetic number, because the mean of its divisors is an integer number (19563456).

Almost surely, 2130006115 is an apocalyptic number.

130006115 is a deficient number, since it is larger than the sum of its proper divisors (26501533).

130006115 is an equidigital number, since it uses as much as digits as its factorization.

130006115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 83389.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 130006115 is about 11402.0224083274. The cubic root of 130006115 is about 506.5876446955.

Adding to 130006115 its reverse (511600031), we get a palindrome (641606146).

The spelling of 130006115 in words is "one hundred thirty million, six thousand, one hundred fifteen".

Divisors: 1 5 313 1565 83071 415355 26001223 130006115