Search a number
-
+
130008023 = 1181110083
BaseRepresentation
bin1111011111111…
…00001111010111
3100001122002110222
413233330033113
5231240224043
620522304555
73136023065
oct757741727
9301562428
10130008023
1167427a52
123765815b
1320c1c332
14133a3035
15b630d68
hex7bfc3d7

130008023 has 4 divisors (see below), whose sum is σ = 130119288. Its totient is φ = 129896760.

The previous prime is 130007987. The next prime is 130008037. The reversal of 130008023 is 320800031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130008023 - 28 = 130007767 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130007992 and 130008010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130008223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53861 + ... + 56222.

It is an arithmetic number, because the mean of its divisors is an integer number (32529822).

Almost surely, 2130008023 is an apocalyptic number.

130008023 is a deficient number, since it is larger than the sum of its proper divisors (111265).

130008023 is a wasteful number, since it uses less digits than its factorization.

130008023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111264.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 130008023 is about 11402.1060773876. The cubic root of 130008023 is about 506.5901229494.

Adding to 130008023 its reverse (320800031), we get a palindrome (450808054).

The spelling of 130008023 in words is "one hundred thirty million, eight thousand, twenty-three".

Divisors: 1 1181 110083 130008023