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1300093937 is a prime number
BaseRepresentation
bin100110101111101…
…1101101111110001
310100121100121121022
41031133131233301
510130311001222
6333001305225
744134421222
oct11537355761
93317317538
101300093937
116079618aa
12303495215
1317946b96c
14c4947249
157920d042
hex4d7ddbf1

1300093937 has 2 divisors, whose sum is σ = 1300093938. Its totient is φ = 1300093936.

The previous prime is 1300093919. The next prime is 1300093939. The reversal of 1300093937 is 7393900031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1253089201 + 47004736 = 35399^2 + 6856^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300093937 - 28 = 1300093681 is a prime.

Together with 1300093939, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300093897 and 1300093906.

It is not a weakly prime, because it can be changed into another prime (1300093939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650046968 + 650046969.

It is an arithmetic number, because the mean of its divisors is an integer number (650046969).

Almost surely, 21300093937 is an apocalyptic number.

It is an amenable number.

1300093937 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300093937 is an equidigital number, since it uses as much as digits as its factorization.

1300093937 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15309, while the sum is 35.

The square root of 1300093937 is about 36056.8154029165. The cubic root of 1300093937 is about 1091.4191701647.

Adding to 1300093937 its reverse (7393900031), we get a palindrome (8693993968).

The spelling of 1300093937 in words is "one billion, three hundred million, ninety-three thousand, nine hundred thirty-seven".