Base | Representation |
---|---|
bin | 111100100010100110… |
… | …0110101001010111110 |
3 | 110102120121202211011202 |
4 | 1321011030311022332 |
5 | 4112230030312202 |
6 | 135420433415502 |
7 | 12251524565624 |
oct | 1710514651276 |
9 | 412517684152 |
10 | 130010010302 |
11 | 50156297007 |
12 | 2124410a592 |
13 | c34bc9aca3 |
14 | 6414953514 |
15 | 35adb8e802 |
hex | 1e453352be |
130010010302 has 4 divisors (see below), whose sum is σ = 195015015456. Its totient is φ = 65005005150.
The previous prime is 130010010293. The next prime is 130010010313. The reversal of 130010010302 is 203010010031.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×1300100103022 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32502502574 + ... + 32502502577.
It is an arithmetic number, because the mean of its divisors is an integer number (48753753864).
Almost surely, 2130010010302 is an apocalyptic number.
130010010302 is a deficient number, since it is larger than the sum of its proper divisors (65005005154).
130010010302 is an equidigital number, since it uses as much as digits as its factorization.
130010010302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65005005153.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 130010010302 its reverse (203010010031), we get a palindrome (333020020333).
The spelling of 130010010302 in words is "one hundred thirty billion, ten million, ten thousand, three hundred two".
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