Search a number
-
+
130010010302 = 265005005151
BaseRepresentation
bin111100100010100110…
…0110101001010111110
3110102120121202211011202
41321011030311022332
54112230030312202
6135420433415502
712251524565624
oct1710514651276
9412517684152
10130010010302
1150156297007
122124410a592
13c34bc9aca3
146414953514
1535adb8e802
hex1e453352be

130010010302 has 4 divisors (see below), whose sum is σ = 195015015456. Its totient is φ = 65005005150.

The previous prime is 130010010293. The next prime is 130010010313. The reversal of 130010010302 is 203010010031.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1300100103022 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32502502574 + ... + 32502502577.

It is an arithmetic number, because the mean of its divisors is an integer number (48753753864).

Almost surely, 2130010010302 is an apocalyptic number.

130010010302 is a deficient number, since it is larger than the sum of its proper divisors (65005005154).

130010010302 is an equidigital number, since it uses as much as digits as its factorization.

130010010302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65005005153.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 130010010302 its reverse (203010010031), we get a palindrome (333020020333).

The spelling of 130010010302 in words is "one hundred thirty billion, ten million, ten thousand, three hundred two".

Divisors: 1 2 65005005151 130010010302