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1300100212310 = 25130010021231
BaseRepresentation
bin10010111010110100000…
…000101110011001010110
311121021210012220202200012
4102322310000232121112
5132300101123243220
62433131403320222
7162633460316504
oct22726400563126
94537705822605
101300100212310
11461407749189
1218bb74b20072
13957a2ab3773
1446cd49d3674
1523c42b1cac5
hex12eb402e656

1300100212310 has 8 divisors (see below), whose sum is σ = 2340180382176. Its totient is φ = 520040084920.

The previous prime is 1300100212291. The next prime is 1300100212339. The reversal of 1300100212310 is 132120010031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13001002123102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65005010606 + ... + 65005010625.

It is an arithmetic number, because the mean of its divisors is an integer number (292522547772).

Almost surely, 21300100212310 is an apocalyptic number.

1300100212310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1300100212310 is a deficient number, since it is larger than the sum of its proper divisors (1040080169866).

1300100212310 is a wasteful number, since it uses less digits than its factorization.

1300100212310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130010021238.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1300100212310 its reverse (132120010031), we get a palindrome (1432220222341).

The spelling of 1300100212310 in words is "one trillion, three hundred billion, one hundred million, two hundred twelve thousand, three hundred ten".

Divisors: 1 2 5 10 130010021231 260020042462 650050106155 1300100212310