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130010032021 is a prime number
BaseRepresentation
bin111100100010100110…
…0111010011110010101
3110102120121210220222011
41321011030322132111
54112230032011041
6135420434104221
712251525016142
oct1710514723625
9412517726864
10130010032021
1150156301361
122124411b071
13c34bca7b3c
14641495b3c9
1535adb95e81
hex1e4533a795

130010032021 has 2 divisors, whose sum is σ = 130010032022. Its totient is φ = 130010032020.

The previous prime is 130010031973. The next prime is 130010032057. The reversal of 130010032021 is 120230010031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91137572100 + 38872459921 = 301890^2 + 197161^2 .

It is a cyclic number.

It is not a de Polignac number, because 130010032021 - 29 = 130010031509 is a prime.

It is a super-2 number, since 2×1300100320212 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130010031992 and 130010032010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010032121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005016010 + 65005016011.

It is an arithmetic number, because the mean of its divisors is an integer number (65005016011).

Almost surely, 2130010032021 is an apocalyptic number.

It is an amenable number.

130010032021 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010032021 is an equidigital number, since it uses as much as digits as its factorization.

130010032021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 130010032021 its reverse (120230010031), we get a palindrome (250240042052).

The spelling of 130010032021 in words is "one hundred thirty billion, ten million, thirty-two thousand, twenty-one".