Base | Representation |
---|---|
bin | 11000001101110101… |
… | …11001010011000111 |
3 | 1020120001200110000020 |
4 | 30012322321103013 |
5 | 203111224113411 |
6 | 5550024350223 |
7 | 640114466265 |
oct | 140672712307 |
9 | 36501613006 |
10 | 13001004231 |
11 | 55718009a6 |
12 | 262a015373 |
13 | 12c2663b17 |
14 | 8b494b435 |
15 | 51159e606 |
hex | 306eb94c7 |
13001004231 has 4 divisors (see below), whose sum is σ = 17334672312. Its totient is φ = 8667336152.
The previous prime is 13001004227. The next prime is 13001004253. The reversal of 13001004231 is 13240010031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13001004231 - 22 = 13001004227 is a prime.
It is a super-2 number, since 2×130010042312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13001004231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13001008231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2166834036 + ... + 2166834041.
It is an arithmetic number, because the mean of its divisors is an integer number (4333668078).
Almost surely, 213001004231 is an apocalyptic number.
13001004231 is a deficient number, since it is larger than the sum of its proper divisors (4333668081).
13001004231 is an equidigital number, since it uses as much as digits as its factorization.
13001004231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4333668080.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 13001004231 its reverse (13240010031), we get a palindrome (26241014262).
The spelling of 13001004231 in words is "thirteen billion, one million, four thousand, two hundred thirty-one".
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