Base | Representation |
---|---|
bin | 11101100011111001010110… |
… | …100011111100000000001110 |
3 | 122001022211211021002221001100 |
4 | 131203321112203330000032 |
5 | 114020041202222430220 |
6 | 1140301453203523530 |
7 | 36245630532012600 |
oct | 3543712643740016 |
9 | 561284737087040 |
10 | 130010112311310 |
11 | 38474a85052400 |
12 | 126b89b76895a6 |
13 | 5770b93606a4a |
14 | 24167471d9170 |
15 | 1006cdc23dd90 |
hex | 763e568fc00e |
130010112311310 has 216 divisors, whose sum is σ = 432210715169688. Its totient is φ = 27015088161600.
The previous prime is 130010112311257. The next prime is 130010112311347. The reversal of 130010112311310 is 13113211010031.
130010112311310 is a `hidden beast` number, since 1 + 30 + 0 + 1 + 0 + 1 + 12 + 311 + 310 = 666.
130010112311310 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1300101123113102 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 107 ways as a sum of consecutive naturals, for example, 121287676 + ... + 122354895.
It is an arithmetic number, because the mean of its divisors is an integer number (2000975533193).
Almost surely, 2130010112311310 is an apocalyptic number.
130010112311310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130010112311310 is an abundant number, since it is smaller than the sum of its proper divisors (302200602858378).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130010112311310 is a wasteful number, since it uses less digits than its factorization.
130010112311310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243642620 (or 243642599 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 130010112311310 its reverse (13113211010031), we get a palindrome (143123323321341).
The spelling of 130010112311310 in words is "one hundred thirty trillion, ten billion, one hundred twelve million, three hundred eleven thousand, three hundred ten".
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