13001011319 has 2 divisors, whose sum is σ = 13001011320. Its totient is φ = 13001011318.

The previous prime is 13001011279. The next prime is 13001011321. The reversal of 13001011319 is 91311010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13001011319 - 2⁸ = 13001011063 is a prime.

It is a super-2 number, since 2×13001011319² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 13001011321, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13001011319.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001011339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500505659 + 6500505660.

It is an arithmetic number, because the mean of its divisors is an integer number (6500505660).

Almost surely, 2^13001011319 is an apocalyptic number.

13001011319 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001011319 is an equidigital number, since it uses as much as digits as its factorization.

13001011319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 13001011319 in words is "thirteen billion, one million, eleven thousand, three hundred nineteen".